How To Make Simple Clap Switch Circuit Working

Components Required

1-mic 1k 4.7k BC547 X2 470R 0.1uf X2 47k 100uf 330R 555 timers led 9v battery

Circuit Diagram

What is 555 Timer???

Basically, 555 timer is an 8-pin integrated chip which has capable of producing accurate time delays or oscillation. By connecting different values of resistor and capacitor to a 555 timer we can use it for countless applications. In simple, it was operating in 3 different modes Astable State “Here the output pulse was continuously switches the state(high – low).” Once we power up the circuit, there is no stable state in the output. Means, it will oscillate at a particular frequency depending upon the RC (resistor – capacitor) values connected with the 555 timer. Either we can increase or decrease the frequency by changing RC values. Monostable state “for a single low trigger input, the output pulse goes to high (we can increase or decrease the ‘high state’ time )and come back to low. “ In simple, its an one pulse mode. By default the output of this circuit will be low (‘0’). when we give a low signal to a trigger pin. The output will goes to high (‘1’) for a certain time and it will come back to the low state. The time for which the output stays high can be controlled by a suitable RC values. Bistable state “ It is possible to set the output either high or low, by providing low values for a particular ‘ TRIGGER’ or ‘ RESET ‘ pin.” in this circuit, we have two switches called ‘ TRIGGER’ and ‘ RESET ‘. Once the TRIGGER is set to LOW, the output will stays HIGH until the RESET set to LOW. in simple, TRIGGER == LOW –> OUTPUT = HIGH RESET == LOW –> OUTPUT = LOW TRIGGER==RESET==LOW –> OUTPUT =HIGH Our aim is to switch on the light for a particular time.. so for this kind of application obviously we need to use MONOSTABLE mode.

How to

Get a monostable output using 555 timer??? The above figure shows the connection of the 555 to get the monostable output. The values of the resistor R and the capacitor C decides how long the output pulse should stay high and time can be calculated using the following equation. Time (secs) = 1.1 * R1 * C1 Where, R – Resistance in ohms C – Capacitance in farads So, when we give a low input to the trigger pin ( pin 2). We can get the high output in the output pin (pin 3). According to the values of the resistor and capacitor the width of the output pulse will be increased or decreased. For eg., R = 4.5k ohms C = 1000uf Time (secs) = 1.1 X (4.5 X 1000) X (1000 X 10 ^ -6) = 4.95 secs Means, the output pulse will stay high for 4.95 seconds. After 4.95 the pulse will come back to low state.

Working

Consider the above circuit into 2 parts, the job of the left part of this circuit is to give the low signal to the right part, which has 555 timer. We already seen the right part of the circuit in “ how to get the monostable output using 555 timer “. According to that, all we have to do is to provide a low signal to the 555s TRIGGER pin (pin 2) to switch on the light for a desired time. NOTE : By default T1 is on and T2 is off. When we power up the circuit, the current will flow from source to the (+ve) mic and leaves at (-ve). Due to the low resistance of the mic the sufficient amount of current will flow to the base of T1. That current helps the T1 to turn on. NOTE : the resistance of the mic will become HIGH when it detect the sound. Due to this, the voltage across the collector-emitter of T1 is zero. So that no voltage across base-emitter of T2 that is the reason why the T2 is in off state by default. When T2 is turned off the voltage across collector-emitter of T2 was almost equal to the source voltage. As discussed before trigger requires low signal to on the 555. When the sound was detected by the mic the resistance of the mic will become high. Due to this, there is no current flow to the base of T1 which makes the T1 to turn OFF. Due to this, the voltage across the collector-emitter of T1 was high, this makes the T2 to turn ON. Once the T2 was in ON, the voltage across collector-emitter of T2 will be low. This LOW was sensed by the trigger pin (pin 2), which makes the 555 to produce the monostable output.